本经验介绍含0.5π+α诱珑廛躬儆导类型三角函数的不定积分，即求∫sin(0.5π+α)dα，∫cos(0.5π+α)dα，∫tan（0.5π+α)dα，∫cot烫喇霰嘴(0.5π+α）dα，∫sec(0.5π+α)dα，∫csc(0.5π+α)dα的步骤。
工具/原料
三角函数基本知识
不定积分基本知识
1.含0.5π+α三角函数的诱导公式
1、sin(π/2+α)=cosαcos(π/2+α)=−sinαtan(π/2+α)=-cotαcot(π/2+α)=-tanαsec(π/2+α)=-cscαcsc(π/2+α)=secα
2、图例解析如下：
3.cos(0.5π+α)
1、∫cos(π/2+α)dα=∫cos(π/2+α)d(π/2+α)=sin(π/2+α)+c=-cosα+c
2、图例解析如下：
5.cot(0.5π+α)
1、∫cot(π/2+α)dα=∫[cos(π/2+α)d(π/2+α)/ sin(π/2+α)]=∫d sin(π/2+α)/sin(π/2+α)=ln|sin(π/2+α)|+c=ln|cosα|+c
2、图例解析如下：
7.csc(0.5π+α)
1、∫csc(π/2+α)d拿骛蟊痊α=∫d(π/2+α)/ sin(π/2+α)=∫sin(π/2+α)d(π/2+α)/ [sin(π/2+珍提疮翘α)]^2=-∫dcos(π/2+α)/ {1-[cos(π/2+α)]^2}=-∫dcos(π/2+α)/ {[1-cos(π/2+α)][1+ cos(π/2+α)]}=-(1/2){∫dcos(π/2+α)/ [1-cos(π/2+α)]+∫dcos(π/2+α)/ [1+cos(π/2+α)]}=-(1/2)ln{[1+cos(π/2+α)]/ [1-cos(π/2+α)]}+c=-(1/2)ln[(1-sinα)/(1+sinα)]+c=-(1/2)ln[(1-sinα)^2/(cosα)^2]+c=-ln|(1-sinα)/cosα|+c=-ln|secα-tana|+c
2、图例解析如下：
